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    <h1>✅ Adventure 4 — Solutions</h1>
    <div class="subtitle">
      These show how to read the graphs, compute areas, and connect derivatives/integrals to motion.
    </div>


    <div class="card">
      </div>

    
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  <div class="left-col">
<h2>1) Height vs Time</h2>
    <ul>
      <li><code>y(4)=980−5·16=900</code> m</li>
      <li><code>y(10)=980−5·100=480</code> m</li>
      <li>Distance fallen from 4→10: <code>900−480=420</code> m</li>
    </ul>

    <h2>2) Velocity and Distance</h2>
    <ul>
      <li>Speed magnitude: <code>|v(t)|=gt=10t</code> (m/s)</li>
      <li>Area 0→4: triangle <code>½·4·40=80</code> m</li>
      <li>Area 0→10: triangle <code>½·10·100=500</code> m</li>
      <li>Check with height: <code>980−y(4)=80</code> and <code>980−y(10)=500</code> ✓</li>
    </ul>

    <h2>3) Hitting the Ground</h2>
    <ul>
      <li><code>980−5t²=0 → t²=196 → t=14</code> s</li>
      <li>Impact speed magnitude: <code>|v(14)|=10·14=140</code> m/s</li>
      <li><code>140×3.6=504</code> km/h</li>
    </ul>

    <h2>4) Acceleration Check</h2>
    <ul>
      <li>Rectangle area from 4→10: <code>10·6=60</code> m/s</li>
      <li>Meaning: area under acceleration = change in velocity. <code>v(10)−v(4)=100−40=60</code> ✓</li>
    </ul>

    <h2>★ Calculus (Derivatives + Integrals)</h2>
    <ul>
      <li><code>y(t)=980−5t² → v(t)=−10t</code> (negative means y decreases). Speed = <code>10t</code>.</li>
      <li><code>a(t)=v′(t)=−10</code> (downward). Magnitude is 10.</li>
      <li>Integrate back (using initial conditions): <code>v(t)=∫(−10)dt=−10t</code>, <code>y(t)=∫(−10t)dt=980−5t²</code>.</li>
    </ul>

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Anon7 - 2021